Atomic number z=117. Number of protons=117. electronic configuration is [Rn]5f¹?6d¹?7s²7p?. Belongs to group 17– Halogen Family. 11) atomic number =z=120. number of protons= 120. so, electronic configuration is [Uuo]8s². element belongs to group 2 —Alkali earth family.
9/24/2019 · Question From – NCERT Chemistry Class 11 Chapter 03 Question – 003 CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES CBSE, RBSE, UP, MP, BIHAR BOARD Q…
(i) The electronic configuration of element with Z = 117 can be represented as This element belongs to Group 17 (halogen family). (ii) The electronic configuration of element with Z = 120 can be represented as This element belongs to Group 2 (alkaline earth metals).
Click here??to get an answer to your question ? Problem 3.3 The elements Z= 117 and 120 have not yet been discovered. In which family / group would you place these elements and also give the electronic configuration in each case.
The elements Z = 117 and 120 have not yet been discovered. In which family / group would you place these elements and also give the electronic configuration in each case.
The elements Z = 117 and 120 have not yet been discovered. In which family/group would you place these elements and also give the electronic configuration in each case. Answer: The last period, i.e. 7th period of the extended form of periodic table will have the element with atomic number 118 (Noble gas). Thus, the element 117 will belong to …
$begingroup$ You would place Z = 120 in the second group, Alkali Earth Metals, as that element completely fills the 8s orbital. Z = 117 is Tennessine, which is a group 17 Halogen and has already been discovered. $endgroup$ – JERRY_XLII Sep 17 ’19 at 4:43
